10x^2+25=35x

Solution for 10x^2+25=35x equation:

10x^2+25=35x

We move all terms to the left:

10x^2+25-(35x)=0

a = 10; b = -35; c = +25;
Δ = b2-4ac
Δ = -352-4·10·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-15}{2*10}=\frac{20}{20}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+15}{2*10}=\frac{50}{20}
=2+1/2
$